OA E:
The traditional way to do this:
L1 passes through points (2,-2) and (8,0)
slope of L1 = 2/6 = 1/3
Since L1*L2 = -1 => L2 = -3
So slope intercept equation of L2 =
y = -3x + c
it passes through (-2,2) =>
-2 = -6 + c => C = 4 (Y intercept is 4)
The trick to the question is knowing to use the correct forms of equation of line to save time.
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Using backsolving:
L1 passes through points (2,-2) and (8,0) => slope of L1 = 1/2 .. so slope of L2 must be -3 ... We know L2 passes through (-2,2) lets take each choice which represents Y intercept hence point (0,y)
A) (0,12) .. slope = (12-2)/(0+2) = 5 NO
B) (0,-12) .. slope = -5 (no need to calculate, just see from above)
C) (0,8/3) = (8/3 - 2)/(0+2) = something with 3 in denominator. no
D) (0,-8/3) = ... there will still be 3 in denominator .. no
Has to be E
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I deally, seeing that 12 didnt work, I wouldnt even have considered -12 and similarly for 8/3 ... This is a good example where using backsolving in the GMAT Test may save you a few precious seconds in the . However it doesn't help that the answer is "none of these" it may lead to second guessing so be careful.