1At a certain bookstore, each notepad costs x dollars and each markers costs y dollars. If $10 is enough to buy 5 notepads and 3 markers, is $10 enough to buy 4 notepads and 4 markers instead?

1). each notepad cost less than $1

2). $10 is enough to buy 11 notepads


2Does the integer k have a factor p such that 1<p<k?

1). k>4!

2). 13!+2<= k<=13!+13


3Is m+z>0

1). m-3Z>0

2). 4z-m>0


4 If x and y are integers greater than 1, is x a multiple of y?

1). 3y^2+7y=x

2). x^2-x is a multiple of y


5On Jane's credit card account, the average daily balance for a 30-day billing cycle is average (arithmetic mean) of the daily balances at the end of the 30 days. At the beginning of a certain 30-day billing cycle, Jane's credit card account had a balance of $600. Jane made a payment of $300 on the account during the billing cycle. If no other amounts were added to or subtracted from the account during the billing cycle, what was average daily balance on Jane's account for the billing cycle?

1). Jane's payment was credited on the 21st day of the billing cycle.

2). The average daily balance through the 25th day of the billing cycle was $540.

1.B
2.B
3.E
4.D
5.D

OAs?

1.E
2.B
3.E
4.D
5.D

Not sure abt the first one.....can anyone explain the 1st one??

thanks in advance!

1)E
2)B
3)C
4)A
5)D

Cross check OA from whois....
:clap:




1)E
2)B
3)C
4)A
5)D

Answer for the 1st one is D

Islanderridz the explaination is as follows:

ST1) Let us take the maximum possible value of Notepad = .99$
Taking this value we get the cost of marker as = 1.68$ from condition given.
Thus the value of 4notepads + 4 markers > 10
For all other (smaller) values of notepad, we will get even higher value of marker, thus even father away from the sum of 10$. So we can 'Definitely' say that the money is not enough.
ST2) Let us consider the boundary case in which 11 notepads completely utilize 10$. In this case, cost of each notepad will be 10/11 $.
Thus cost of each marker will be: 20/11 $ from condition 1.
Thus applying these values in condition 2 we get that 4notepads + 4markers > 10
For all other smaller values of notepad, the value will still be greater.
So we can 'Definitely' say that the money will not be enough.

Verify and tell if its right...

Answers for the remaining:
2) B
3) C
4) A
5) D

Does the word 'enough' in the 1st question means equal to ?

i think it means greater than.......

for eg. if it says that $10 are enough to buy 5 notepads and 3 marker than it means that the price is below ten or $10 are greater than the price of 5 notepads and 3 markers. In that case answer to the question is E

you r right guys...enough does not mean "equal to"...silly mistake...

Guys whats the answer of qn 3 I thought the answer was e
Cud aneebody explain pls

N also

N also how did u guys

N also how did u guys determine that there is no prime no. between 131+2 and 13 !+13 .

N also how did u guys determine that there is no prime no. between 131+2 and 13 !+13 . Pleez explain
Nakul where r u ?

Hi dreamer,
Sorry for the delay...here i am :)

OK starting with Q3)

St1 alone - Clearly insufficient. Since we just know that m>3z or z<m/3. But still both m and z can be -ve.

St2 alone - Clearly insufficient. Since we just know that m<4z or z<m/4. But still both can be -ve as from St1.

Combining both, we get that 3z<m<4z. From this we can be sure that z cannot be -ve since in that case 4z < 3z and thus any number which > 3z will also be greater than 4z. Hence z has to be +ve. Now since z is +ve, m will also be +ve and inturn their sum will also be +ve.

I hope i could clarify this...:)

As for Q2)

The explaination:

St1 alone - Clearly insufficient.

St2 alone - Given: 13!+2 <= k <= 13!+13
Now let us simplify our stuff by a smaller example :-

Let this be as 5!+2 to 5!+5

Now 5! = 1*2*3*4*5
5!+2 = 1*2*3*4*5 + 2 => 2(1*3*4*5 + 1) so divisible by 2.
5!+3 = 1*2*3*4*5 + 3 => 3(1*2*4*5 + 1) so diviaible by 3.
5!+4 = 1*2*3*4*5 + 4 => 4(1*2*3*5 + 1) so divisible by 4.
5!+5 = 1*2*3*4*5 + 5 => 5(1*2*3*4 + 1) so divisible by 5.

In general
this will be true for the range n!+2 to n! + n (both inclusive).

Dear Nakul thanks

I have one doubt still left . Why cant z get -ve. Lets say it gets negative , then the only change that occurs is that 4z becomes less than m and 3 z becomes greater than m ..... which is the case when z is -ve. So, I am not convinced that z cant get negative.:yikes:


Explanation for 13 ! + 2 was superb ... Thanks:b

Ok...to clarify, let us take a -ve value of z = -5 (say)

3z = -15 and 4z = -20. So 3z > 4z.

From st1 we get that m>3z, So m can be any value > -15. {-14,-13,-12,-11...,0,1,2,3,....}

From 2nd statement we get x<-20. So m can have any value < -20. {-21, -22, -23, -24.....}

So we can say that a -ve value of z will never satisfy both the conditions. Thus z has to be a +ve value.

Thanks a lot Nakul.
It grew big on me ....

Guys
What about the Question No 5?
I am totally lost
What are they saying?
300$ how will become 540 ...please help

@nakul need help
in Qn no 4 why cant statement B also helps to get the answer
when we simplfy x(x-1)/y cant we say from dis xpression that X is multiple of Y?
bt yes OA is A

HI shivaqif...

In Q4, St2 says that x^2-x is a multiple of y. We are required to find "if X is a multiple of Y".
Ok...now we can simplify this expression to x(x-1) = y. If you just look into this statement, you will find that you can surely say that "Y is a multiple of X" but not "X is a multiple of Y".
To make things clearer, we can take any value of X, say 5
5.(5-1) = 20 and 20 is a multiple of 5. But 5 is not a multiple of 20.

Guys
What about the Question No 5?
I am totally lost
What are they saying?
300$ how will become 540 ...please help

As for the 5th question:
Answer will be D.

The Q-stem says: Balance in Jane's a/c at the start of a 30-day billing cycle wa 600$. Now some time during this cycle, she withdrew 300$. So we need to know the average balance at the end of the month.

St1 alone - We are told that the withdrawl was made on the 21st day. So
(20*600 + 10*300)/30 = Avg. balance throughout the month. Hence sufficient.

St2 alone - We are told that avg till 25th day was 540. Since it was < 600, we can be sure that the withdrawl has already been made. Hence,

(25*540 + 5*300)/30 = Avg. balance throughout the month. Hence sufficient.

Hence D.

I hope this helps...

done:b

HI shivaqif...

In Q4, St2 says that x^2-x is a multiple of y. We are required to find "if X is a multiple of Y".
Ok...now we can simplify this expression to x(x-1) = y. If you just look into this statement, you will find that you can surely say that "Y is a multiple of X" but not "X is a multiple of Y".
To make things clearer, we can take any value of X, say 5
5.(5-1) = 20 and 20 is a multiple of 5. But 5 is not a multiple of 20.