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Thread: PS find the mathematical operator

  1. December 2nd, 2008 09:43 PM #1
    dauntless18
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    PS find the mathematical operator

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    Posted by: dauntless18

    If the operation # is defined for all the integers n and w by x#w
    x#w=2^x/2^w, then (3#1)#3=


    A. 4
    B. 3
    C. 8
    D. 2
    E. 7
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  2. December 2nd, 2008 11:40 PM #2
    cool_sarav
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    Hi,

    (3#1) = 2^3/2 = 4
    Therefore ,
    4#3 = 2^4/2^3 = 2
    So the answer is : D

    Please correct me if wrong.
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