Thread: integers

100 is not divisible by 3
so we can take (200-100)/3 => 100/3 => 33.3

So 33 integers are divisble.

IMO A

is A the correct answer?

yes

IMO A

first number divisible by 3 = 102
last number divisibl by 3 = 198
198 - 102 = 96
96 / 3= 32 number after 102.. including 102 = total 33 numbers.

I like the theman1 approach too..

102/3=34
198/3=66
so total nbrs in betn excluding both = 66-34-1=31.

ok so is there a rule or special sum here that we take the difference of the two numbers then divide it by 3? thanks